Need Programming Algorithm

[David Taylor]

It's not pseudocode, but try these changes to Simon's algorithm.

Make each list the same length (the maximum number of values for a 
property) and fill the unneeded indexes in each list with some unique 
marker.  Test for the marker in each loop.  When you find it, drop 
out of the current loop and all lower loops.  (To skip the lower 
loops, set a flag when you find the marker and have each loop drop 
out without doing anything if the flag is set. Clear the flag each 
time the first loop starts.)

>Hi Simon,
>
>You are right, except if one or more of the lists is empty, it 
>short-circuits everything.
>
>Rick
>
>Hi Rick.
>
>Unless I greatly misunderstand you, I believe you just need a series of
>nested loops, driven by a series of string lists.
>
>The rough algorithm is:
>
>New StringList NewVar(vlFirst);
>// Go through the first row of the table and add members to the
>stringlist.
>New StringList NewVar(vlSecond);
>// Go through the next row of the table and add members to the
>stringlist.
>New StringList NewVar(vlThird);
>// Go through the next row of the table and add members to the
>stringlist.
>
>// (If you don't know how many rows you'll have, you could assemble them
>in an EVector object.)
>
>// Now use nested loops:
>
>Loop While(vFirstIndex <= vlFirst.count) LoopVar(vFirstIndex) InitVal(1)
>Incr(1)
>   Set vFirstText = vlFirst[vFirstIndex];
>
>   Loop While(vSecondIndex <= vlSecond.count) LoopVar(vSecondIndex)
>InitVal(1) Incr(1)
>      Set vSecondText = vlSecond[vSecondIndex];
>
>      write console vFirstText + ' ' + vSecondText + ' ' + vThirdText +
>' ';
>
>      Loop While(vThirdIndex <= vlThird.count) LoopVar(vThirdIndex)
>InitVal(1) Incr(1)
>         Set vThirdText = vlThird[vThirdIndex];
>
>      EndLoop
>   EndLoop
>EndLoop
>
>
>???
>Simon
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  David M. Taylor                 Email: dtaylor at opnet.com
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